Heat Engine, Heat Pump and Refrigeration system

What you will learn

To study the aspects of Second law of Thermodynamics

To understand the statements of Second law of thermodynamics

To get the concept of Equivalence of Kelvin-Planck and Clausius Statement

To get the idea of COP of Heat pumps and Refrigeration

To know the methods of solving numericals on Heat Engine, Heat Pump and Refrigerator

Get idea about Carnot’s theorem and Carnot Cycle.

Know the working principle of Heat Engines, Heat Pumps and Refrigerators .

Description

Course Contents as per syllabus :

Equivalence of Clausius and Kelvin Planck Statement, PMM I and II, Concept of Reversibility and Irreversibility.

Course Objectives:

•To study the aspects of Second law of Thermodynamics

•To understand the statements of Second law of thermodynamics

•To get the concept of Equivalence of Kelvin-Planck and Clausius Statement

•To define Perpetual Machine of IInd Kind (PMM-II)

•To Study Carnot theorem and Carnot Cycle

•To get the knowledge of Heat engine and its efficiency

•To compare Heat pumps and Refrigeration system

•To get the idea of COP of Heat pumps and Refrigeration

•To know the methods of solving numericals on Heat Engine, Heat Pump and Refrigerator

Brief description about  Heat Engine, Refrigerator and Heat pump :

HEAT ENGINE

Based on Kelvin- Planck’s Statement.

It is a device that converts heat to work.

In case of heat engine, efficiency is defined as ratio of work done to heat energy supplied.

Here important criteria is net work done.

Work done by the engine =W = (Q1 – Q2)

Efficiency = Work done / Heat supplied

Efficiency = W / Q1 = (Q1 – Q2) / Q1

                      = (T1-T2 ) / T1

                      = 1 – ( T2 / T1)

REFRIGERATOR


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Based on Clausius Statement.

In case of a refrigerator ,COP is defined which is the ratio of heat absorbed (refrigeration effect) to work done on the system ,Here the important criteria is heat absorbed as refrigeration effect.

Work Done on system = (Q1 – Q2)

COPR = Desired Effect / Work done

            = Q2 / ( Q1 – Q2)

           = T2 / ( T1-T2)

COP is reverse of Efficiency

HEAT PUMP

Based on Clausius Statement.

In case of a heat pump ,COP is defined which is the ratio of heat rejected (refrigeration effect) to work done on the system. Here the important criteria is heat rejected as refrigeration effect.

Work Done on system = (Q1 – Q2)

COPHP = Desired Effect / Work done

                = Q1 / ( Q1 – Q2)

               = T1 / ( T1-T2)

COP HP = COPR + 1

Course Outcomes :

Learner will be able to

•Get idea about limitations of First law of Thermodynamics.

•Can compare between Kelvin and Clausius Statements.

•Understand various statements of Second law of Thermodynamics.

•Have clear idea about Kelvin and Clausius Statement.

•Get idea about Carnot’s theorem and Carnot Cycle.

•Know the working principle of Heat Engines, Heat Pumps and Refrigerators .

•Find out Efficiency of Heat Engines and COP of heat pumps and refrigerators.

English
language

Content

Introduction

Numericals on Steady Flow Energy Equation (SFEE)
Lecture 2: Second Law Of Thermodynamics
Lecture 3: Carnot Engine
Lecture 4: Heat Engines and COP for Heat Pumps and Refrigerators
Lect 5: Numericals on COP and Efficiency- II
Numericals on Efficiency and COP -III